The sides of a triangle are $x^{2} - 3 x y + 8, 4 x^{2} + 5 x y - 3 a n d 6 - 3 x^{2} + 4 x y$ .Find its perimeter.

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Solution

Required perimeter=Sum of three sides

$x^{2} - 3 x y + 8 + 4 x^{2} + 5 x y - 3 + 6 - 3 x^{2} + 4 x y = x^{2} + 4 x^{2} - 3 x^{2} - 3 x y + 5 x y + 4 x y + 8 - 3 + 6 = 2 x^{2} + 6 x y + 11$

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