The sides of a triangular field are 975m, 1050 mand 1125m. If this field is sold at the rate of Rs. 1000 per hectare, find its selling price.

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Solution

Area of the triangle= $\sqrt{s . (s - a) (s - b) (s - c)}$ (by heron's formula)
where s= $\frac{(a + b + c)}{2}$
a=975m, b=1050m, c=1125m
$∴ s = 1575 m$
Area= $\sqrt{1575 (1575 - 975) (1575 - 1050) (1575 - 1125)}$

$\Rightarrow 472500 m^{2}$

$1 h e c t a r e = 10, 000 m^{2}$

$∴ 472500 m^{2} = 47.25 h e c t a r e s$
$\Rightarrow$ selling price of the field will be $47.25 h e c t a r e s \times 1000$
$\Rightarrow= 47250 R s$

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The sides of a triangular field are 975m, 1050 mand 1125m. If this field is sold at the rate of Rs. 1000 per hectare, find its selling price.

Area of the triangle=√s.(s−a)(s−b)(s−c) (by heron's formula)where s=(a+b+c)2a=975m, b=1050m, c=1125m∴s=1575mArea=√1575(1575−975)(1575−1050)(1575−1125)⇒472500m21hectare=10,000m2∴472500m2=47.25hectares⇒ selling price of the field will be 47.25hectares×1000⇒=47250Rs