The correct option is B 1500√3 m2
Let x be HCF. Then sides a=3x;b=5x & c=7x
Perimeter, 3x+5x+7x=300⇒x=20
Then the sides a=60 m; b=100 m & c=140 m
Semiperimeter s=60+100+1402=150 m
Area=√s(s−a)(s−b)(s−c) =√150(150−60)(150−100)(150−140) =√150×90×50×10 =1500√3m2