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Question

The sides of an equilateral triangle are (6x+5y)cm, (7x+3y+1)cm, 2(x+6y-1) cm . find the length of each side 


Solution

since the sides of an eqilateral triangle are equal.
6x+5y=2x+12y-2
or,4x=7y-2
or x=(7y-2)÷4.....(i)

Again 

6x+5y=7x+3y+1
or,x=2y-1......(ii)

Comparing (i)and(ii)we get
2y-1=(7y-2)÷4
or,8y-4=7y-2
or,y=2

Therefore x=3

First side= 28 cm
Second side =28cm
Third side =28 cm

I hope this helps 

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