The sides of an equilateral triangle are given by x+3y,3x+2y−2 and 4x+12y+1 respectively. Find the lengths of the sides of the sides of the triangle.
A
15 units each
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B
12 units each
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C
13 units each
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D
18 units each
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Solution
The correct option is A 15 units each x+3y=3x+2y−2=4x+12y+1Fromthefirsttwo,wegetx+3y=3x+2y−2Soy=2x−2−>eqn1Subvalueofywegetx+3y=7x−6and4x+1/2y+1=4x+x−1+1=5xSincebothareequal7x−6=5xSox=3Subx=3ineqn1y=4Sovalueofasideisx+3y=3+12=15units