Question

The sides of certain triangles are given below. Determine which of them are right triangies.
(i) a = 7cm, b=24 an and c=25cm
(ii) a =9 cm, b= 16cm and c = 18 cm
(iii) a=1.6 cm, b=3.8 cm and c=4 cm
(iv) a =8 cm, b = 10cm and c = 6 cm

Answer 1

1)-

$c^2={25}^2=625a^2+b^2=7^2+{24}^2=49+576=625$
Since $c^2=a^2+b^2$
right triangle

2)-

$c^2={18}^2=324a^2+b^2=9^2+{16}^2=81+256=337$
Since $c^2\ne a^2+b^2$
not right triangle

3)-

$c^2=4^2=16a^2+b^2=3.8^2+{1.6}^2=14.44+2.56=17$
Since
$c^2\ne a^2+b^2$
not right triangle

4)-

$c^2={10}^2=100a^2+b^2=8^2+6^2=64+36=100$
Since
$c^2=a^2+b^2$
so right triangle