Question

The sides of $\Delta$ are $6cm$ ,$8cm$,$10cm$ find its area using heron's formulas

Answer 1

Given:$a=6cm,b=8cm,c=10cm$

Semiperimeter$=s=\frac{a+b+c}{2}=\frac{6+8+10}{2}=\frac{24}{2}=12cm$

By Heron's formula, we have

Area of triangle$=\Delta =\sqrt{s(s-a)(s-b)(s-c)}$

$=\sqrt{12(12-6)(12-8)(12-10)}$

$=\sqrt{12\times 6\times 4\times 2}$

$=\sqrt{4\times 3\times 3\times 2\times 4\times 2}$

$=4\times 3\times 2=24sq.cms$