The sides of $Δ ABC$ are 6 cm, 8 cm and 10 cm. Find the perimeter of the larger triangle which is similar to $Δ ABC$ if the ratio of corresponding sides is 2.

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Solution

Let $Δ XYZ$ be the larger triangle similar to $Δ ABC$ .

Given: The ratio of corresponding sides is 2.

Since ratio of their corresponding sides is 2, the ratio of their perimeter will also be 2.

Perimeter of $Δ ABC = 6 + 8 + 10 = 24 c m$

$\frac{Perimeter of (Δ XYZ)}{Perimeter of (Δ ABC)} = 2$ ..........(Ratio of perimeters of similar triangles)

$\frac{Perimeter of (Δ XYZ)}{24} = 2$

The perimeter of $Δ XYZ = 24 \times 2 = 48 c m .$

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