Let’s assume the triangle similar to ΔABC to be ΔXYZ. The ratio of corresponding sides is 2.
So, XYAB=YZBC=XZAC=2 (Since it is asked for larger triangle)
⇒XY6=YZ8=XZ10=2
⇒ XY = 12 cm, YZ = 16 cm and XZ = 20 cm.
The perimeter of ΔXYZ is XY + YZ + XZ = 12 + 16 + 20 = 48 cm.