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Question

The signal x(t) is defined as

x(t)=⎪ ⎪⎪ ⎪5sint,0<t<πt+2π<t<2πt22π<t<3π0,otherwise

The energy in the signal is _______.
  1. 293.64

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Solution

The correct option is A 293.64
E=|x(t)|2dt

E=25π0sin2tdt+2ππ(t+2)2dt+3π2π(t2)2dt

E=25π0(1cos2t2)dt+[(t+2)33]2ππ+[(t2)33]3π2π

E=25(π2)+(2π+2)3(π+2)33+(3π2)3(2π2)33=293.64

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