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Nucleophilic Substitution in Alkyl Halides

The silver sa...

Question

The silver salts like $A g B r$ and $A g I$ are coloured because of:

A

d-d transition of electrons

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B

charge transfer

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C

polirisation of halid

{A g}^{+}

by

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D

both (b) and (c)

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Solution

The correct option is A d-d transition of electrons
The silver salts like $A g B r$ and $A g I$ are colored, the color of transition metal ions is due to the presence of unpaired electron . The electrons which absorbs radiations of color that from the visible or UV spectrum and undergo transition from ground state to excited state within d-sub shells,so it is d-d transitions of electrons.

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Similar questions

A g C l

N a C l

are colourless.

N a B r

N a I

are also colourless but

A g B r

A g I

are coloured. This is because:

Q. Solubility product

(K_{s p})

values of the following sparingly soluble salts at

25^{\circ} C

K_{s p}

A g C l 1.8 \times 10^{- 10} A g I 1.1 \times 10^{- 16} P b C r O_{4} 1.8 \times 10^{- 14} A g B r 3.3 \times 10^{- 13}

The least soluble and the most soluble salts respectively are:

Q. A solution contains

[I^{-}] = [B r^{-}] = [C l^{-}] = 0.2 M

each.
Then which of the following statements regarding precipitation of sparingly soluble salts

A g C l

A g B r

A g I

is correct:
Given :

S a l t K_{s p} (m o l L^{- 1})^{2}

A g C l 1.8 \times 10^{- 10}

A g B r 5 \times 10^{- 13}

A g I 8.3 \times 10^{- 17}

Q. Find the number of halides which are insoluble in water.
AgF, AgCl, AgBr, AgI, NaCl,

The $K_{s p}$ of $A g_{2} C r O_{4}, A g C l, A g B r$ and AgI are respectively, $1.1 \times 10^{- 12}, 1.8 \times 10^{- 10}, 5.0 \times 10^{- 13}, 8.3 \times 10^{- 17}$ . Which one of the following salts will precipitate last if $A g N O_{3}$ solution is added to the solution containing equal moles of NaCl, NaBr, Nal and $N a_{2} C r O_{4}$ ?

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