Question

The simplest form of $\frac{1095}{1168}$ is

(a) $\frac{17}{26}$
(b) $\frac{25}{26}$
(c) $\frac{13}{16}$
(d) $\frac{15}{16}$

Answer 1

(d) $\frac{15}{16}$

$\frac{1095}{1168}=\frac{1095÷73}{1168÷73}=\frac{15}{16}$

Hence, HCF of 1095 and 1168 is 73.