The simplest form of (x3–1)(x2–1) is
(x2 + 1)/(x+1)
(x2 + x + 1)
(x2 + 2x + 1)/(x+1)
(x2 + x + 1)/(x+1)
(x3–1)/(x2–1) = [(x–1)(x2+x+1)][(x−1)(x+1)]
= [(x2+x+1)](x+1)
x+1 is a factor of the polynomialA. x3+x2−x+1B. x3+x2+x+1C. x4+x3+x2+1D. x4+3x3+3x2+x+1