Question

The simplest form of $\sqrt[5]{32}$ is .

Answer 1

The number 32 can be written in exponential form as:

$$\begin{gathered} 32=2\times 2\times 2\times 2\times 2 \\ =2^5 \end{gathered}$$

Thus,

$$\begin{gathered} \sqrt[5]{32}=\sqrt[5]{2^5} \\ ={\left(2^5\right)}^{\frac{1}{5}} \\ =2^1\left[\because {\left(a^m\right)}^n=a^{mn}\right] \end{gathered}$$

Final Answer: Therefore, the simplest form is 2.