The simplest form of the expression 10−√−121−√−27 is
We need to find simplest form of 10−√−121−√−27
=10−2i√31−3i√3
Taking conjugate, we get
= 10−2√−31−3√−3×1+3i√31+3i√3
= 10−2√−31−3√−312−(3i√3)2
= 10+30i√3−2i√3−18i228
= 10+28i√3+1828
= 28(1+i√3)28
= 1+i√3