The simplest formula of a compound containing 50% of element $X (a t o m i c m a s s = 10)$ and 50% of the element $Y (a t o m i c m a s s = 20)$ by weight is :

X Y

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X_{2} Y

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X Y_{2}

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X_{2} Y_{3}

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Solution

The correct option is A $X_{2} Y$
$X_{M} Y_{N}$ : Assume
Given atomic mass X $=$ 10
atomic mass Y $=$ 20

$\frac{m \times X}{m \times X + n \times Y} = \frac{1}{2}$ (50%)
$\Rightarrow 2 m X = m X + n Y \Rightarrow m X = n Y \Rightarrow \frac{m}{n} = \frac{Y}{X} = \frac{20}{10} = 2 \Rightarrow m = 2 n s i m p l e s t : n = 1, m = 2$

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