Question

The simplest rationalising factor of $\sqrt[3]{3500}$ is

• A. $\sqrt[3]{32}$
• B. $\sqrt[3]{35}$
• C. $\sqrt{3}$
• D. None of these

Answer 1

The correct option is A

$\sqrt[3]{32}$

$\sqrt[3]{3500}=\sqrt[3]{32\times 2\times 5\times 5\times 5}$

Making triplet, we find 2 is required to complete the triplet of 2

$\therefore$ Required factor =$\sqrt[3]{32}$