Question

The simplified value of $\frac{(225{)}^{0.2}\times (225{)}^{0.3}}{(225{)}^{0.8}\times (225{)}^{0.2}}$ is equal to:

• A. $15$
• B. $\frac{1}{15}$
  
• C. $\frac{1}{25}$
• D. $1.5$

Answer 1

Answer: (B)

$\frac{1}{15}$

Given,

$\frac{(225{)}^{0.2}\times (225{)}^{0.3}}{(225{)}^{0.8}\times (225{)}^{0.2}}$

$\therefore \frac{(225{)}^{0.2}\times (225{)}^{0.3}}{(225{)}^{0.8}\times (225{)}^{0.2}}=\frac{1}{(225{)}^{0.8-0.3}}$. ...($\because \frac{a^m}{a^n}=a^{m-n}$)

$=\frac{1}{(225{)}^{0.5}}$ $=\frac{1}{15}$