The size of atomic nucleus is of the order of

10^{- 15} m

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10^{- 10} m

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10^{14} m

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10^{10} m

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Solution

The correct option is A $10^{- 15} m$
Size of nucleus, $R = R_{o} A^{1 / 3}$
where $R_{o} = 1.5 f m = 1.5 \times 10^{- 15} m$
and $A$ is the mass no.
$A^{1 / 3}$ is of order 1,
hence $R$ is of order $10^{- 15} m$

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