The size of carbon nano tube is 25 - 10-9 m and the size of bacterial cell is 5 - m- Find the ratio of size of bacterial cell to carbon nano tube- Given 1 - m - 10-6 m -3 MARKS-

Concept: 1 Mark Application: 2 nbsp;Mark Size of carbon Nano tube nbsp;=25 × 10^ 9 m nbsp;Size of bacterial cell = 5 μ m = 5 × 10^ 6 m Ratio of bacter ...

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Standard IX

Biology

Gram +ve/-ve Bacteria

The size of c...

Question

The size of carbon nano tube is $25 \times 10^{- 9} m$ and the size of bacterial cell is $5 μ m$ . Find the ratio of size of bacterial cell to carbon nano tube. Given $1 μ m = 10^{- 6} m$ [3 MARKS]

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Solution

Concept: 1 Mark
Application: 2 Mark

Size of carbon Nano tube $= 25 \times 10^{- 9} m$

$S i z e o f b a c t e r i a l c e l l = 5 μ m = 5 \times 10^{- 6} m$

Ratio of bacterial cell to carbon nano tube

$= 5 \times 10^{- 6} m : 25 \times 10^{- 9} m$

$= \frac{5 \times 10^{- 6} m}{25 \times 10^{- 9} m}$

$= \frac{200}{1}$

$= 200 : 1$

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The size of carbon nano tube is 25×10−9 m and the size of bacterial cell is 5 μm. Find the ratio of size of bacterial cell to carbon nano tube. Given 1 μm=10−6m [3 MARKS]

Concept: 1 Mark Application: 2 Mark Size of carbon Nano tube =25×10−9 m Size of bacterial cell = 5 μm =5×10−6 m Ratio of bacterial cell to carbon nano tube =5×10−6 m : 25×10−9 m =5×10−6 m25×10−9 m =2001 =200:1

The size of carbon nano tube is $25 \times 10^{- 9} m$ and the size of bacterial cell is $5 μ m$ . Find the ratio of size of bacterial cell to carbon nano tube. Given $1 μ m = 10^{- 6} m$ [3 MARKS]