The slant height of the frustum of a cone is 4 cm and the perimeters of its circular ends are 18 cm and 6 cm. Find the curved surface of the frustum.

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Solution

The slant height of the frustum of the cone is l = 4 cm. The perimeters of the circular ends are 18 cm and 6 cm. Let the radii of the bottom and top circles are r₁ cm and r₂ cm respectively. Then, we have

The curved surface area of the frustum cone is

= 48 Square cm

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The slant height of the frustum of a cone is 4 cm and the perimeters of its circular ends are 18 cm and 6 cm. Find the curved surface of the frustum.

The slant height of the frustum of the cone is l = 4 cm. The perimeters of the circular ends are 18 cm and 6 cm. Let the radii of the bottom and top circles are r1 cm and r2 cm respectively. Then, we have The curved surface area of the frustum cone is = 48 Square cm

The slant height of the frustum of the cone is l = 4 cm. The perimeters of the circular ends are 18 cm and 6 cm. Let the radii of the bottom and top circles are r₁ cm and r₂ cm respectively. Then, we have

The curved surface area of the frustum cone is

= 48 Square cm