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Byju's Answer
Standard XII
Mathematics
Equation of Tangent in Slope Form
The slope ' ...
Question
The slope '
m
' of a tangent through the point
(
7
,
1
)
to the circle
x
2
+
y
2
=
25
satisfies the equation
A
12
m
2
+
7
m
−
12
=
0
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B
16
m
2
−
24
m
+
9
=
0
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C
12
m
2
−
7
m
−
12
=
0
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D
9
m
2
+
24
m
+
16
=
0
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Solution
The correct option is
C
12
m
2
−
7
m
−
12
=
0
Equation of the line passing through
(
7
,
1
)
is
(
y
−
1
)
=
m
(
x
−
7
)
∴
5
=
∣
∣
∣
7
m
−
1
√
1
+
m
2
∣
∣
∣
⇒
25
(
1
+
m
2
)
=
(
7
m
−
1
)
2
⇒
25
m
2
+
25
=
49
m
2
−
14
m
+
1
⇒
24
m
2
−
14
m
−
24
=
0
⇒
12
m
2
−
7
m
−
12
=
0
Suggest Corrections
0
Similar questions
Q.
The slope m of a tangent through the point (7, 1) to the circle
x
2
+
y
2
=
25
satisfies the equation
Q.
Slopes of tangents through (7,1) to the circle
x
2
+
y
2
=
25
satisfy the equation.
Q.
The slope m of a tangent through the point (7, 1) to the circle
x
2
+
y
2
=
25
satisfies the equation
Q.
For hyperbola
x
2
16
−
y
2
12
=
0
and circle
x
2
+
y
2
=
25
, find concyclic points.
Q.
Find the equation of the circle passing through the points of intersection of the circles
x
2
+
y
2
−
4
x
−
6
y
−
12
=
0
and
x
2
+
y
2
+
6
x
+
4
y
−
12
=
0
and intersection the circle
x
2
+
y
2
−
2
x
−
4
=
0
orthogonally.
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