Question

The slope of a line perpendicular to the line $3x=4y+11$ is

• A. $-\frac{4}{3}$
• B. $-\frac{3}{4}$
• C. $\frac{4}{3}$
• D. $\frac{3}{4}$

Answer 1

The correct option is A $-\frac{4}{3}$

Slope of a line perpendicular to the line $3x=4y+11$ is
$\Rightarrow 4y=3x-11$
$\Rightarrow y=\frac{3}{4}x-\frac{11}{4}=\frac{3}{4}$
$\therefore$ Slope of the line perpendicular to this line
$=-\frac{4}{3}$ $(\because m\times n=-1)$