The slope of a velocity-time graph for the free fall of a body under gravity, starting from rest is (Take g=10ms−2.)
A
10m/s2.
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B
−10m/s2.
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C
0m/s2.
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D
1m/s2.
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Solution
The correct option is B−10m/s2. The line on the velocity-time graph for the free fall of a body under gravity is a straight line. A free-falling object is undergoing an acceleration (g = 10ms−2, downward). A further look at the velocity-time graph reveals that the object starts with a zero velocity (as read from the graph) and finishes with a large, negative velocity; that is, the object is moving in the negative direction and speeding up. An object that is moving in the negative direction and speeding up is said to have a negative acceleration. Since the slope of any velocity versus time graph is the acceleration of the object, the constant, negative slope indicates a constant, negative acceleration. Below is the diagrammatic representation.