The slope of Arrhenius plot ln k v-s 1T of first order reaction is -5 - 103 K- The value of Ea of the reaction is- Choose the correct option for your answer- -Given R - 8-314 JK-1 mol-1-

Arrhenius equation k = Ae^ E_a/RT ln k = ln nbsp;A + ln e^ E_a/RT ln k nbsp; = ln A nbsp;E_aR (1T nbsp; ) .......(1) Slope of nbsp; ln nbsp;k ...

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Standard XII

Chemistry

Introduction

The slope of ...

Question

The slope of Arrhenius plot $(ln k v / s \frac{1}{T})$ of first order reaction is $- 5 \times 10^{3} K$ . The value of $E_{a}$ of the reaction is. Choose the correct option for your answer. [Given $R = 8.314 J K^{- 1} m o l^{- 1}]$

- 83 k J m o l^{- 1}

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41.5 k J m o l^{- 1}

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83.0 k J m o l^{- 1}

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166 k J m o l^{- 1}

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Solution

The correct option is B $41.5 k J m o l^{- 1}$
Arrhenius equation

$k = A e^{- E_{a} / R T}$

$ln k = ln A + ln e^{- E_{a} / R T}$

$ln k = ln A - \frac{E_{a}}{R} (\frac{1}{T})$ .......(1)

Slope of $ln k v s \frac{1}{T}$ curve,

$m = - \frac{E_{a}}{R}$

$- 5 \times 10^{3} = - \frac{E_{a}}{R}$

$E_{a} = 5 \times 10^{3} \times 8.314 J / m o l$

$41.57 \times 10^{3} J / m o l$

$= 41.5 k J / m o l$

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Similar questions

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The slope of Arrhenius plot (ln k v/s 1T) of first order reaction is –5×103 K. The value of Ea of the reaction is. Choose the correct option for your answer. [Given R=8.314 JK–1 mol–1]

The correct option is B 41.5 kJ mol–1Arrhenius equation k=Ae−Ea/RT lnk=lnA+lne−Ea/RT lnk=lnA−EaR(1T) .......(1) Slope of lnk vs1T curve, m=−EaR −5×103=−EaR Ea=5×103×8.314 J/mol 41.57×103 J/mol =41.5 kJ/mol

The slope of Arrhenius plot $(ln k v / s \frac{1}{T})$ of first order reaction is $- 5 \times 10^{3} K$ . The value of $E_{a}$ of the reaction is. Choose the correct option for your answer. [Given $R = 8.314 J K^{- 1} m o l^{- 1}]$