Question

The slope of $\pi$ versus $\text{C}$ was made against insulin concentration $\text{c}$. in ${\text{gmL}}^{-1}$ and temperature $27{}^{\circ }\text{C}$. If $\text{C}$ is in ${\text{litre}}^{-1}$ and the slope of line obtained is $4.65\times {10}^{-3}\frac{g}{mL}$, which of the following are not the molar mass $\left({\text{in g mol}}^{-1}\right)$ of insulin?

• A. $9\times {10}^5$
• B. $3\times {10}^5$
• C. $4.5\times {10}^5$
• D. $5.30\times {10}^6$

Answer 1

Answer: (A), (B), (C)

The correct options are
A $9\times {10}^5$
B $3\times {10}^5$
C $4.5\times {10}^5$

Osmotic pressure is given by $\pi =CRT$, $C=\frac{w}{VM}$
$\pi =\frac{w}{V}\frac{RT}{M}$,Where M is the molar mass of insulin
$\therefore slope=\frac{RT}{M}=4.65\times {10}^{-6}g/L$
$\frac{0.0821\times 300}{4.65\times {10}^{-6}}=M=5.30\times {10}^{6}g/mol$