The slope of tangent to the curve y=(x−1)ex at point, where curve intersects the x− axis, is
A
e−1
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B
e
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C
e+1
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D
2e
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Solution
The correct option is Be Given : y=(x−1)ex
For y=0⇒x=1(∵ex≠0)
Differentiating both sides w.r.t. x ⇒dydx=xex
Now, the slope of tangent dydx∣∣∣(1,0)=1⋅e1=e ∴ slope of tangent is equal to e.