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Question

The slope of the graph of the maximum kinetic energy (in joule) of the photoelectrons versus the frequency difference (vv0) in a photoelectric experiment is a measure of


A

h

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B

h/e

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C

e/h

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D

1/h

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Solution

The correct option is A

h


Here h = Planck’s constant and e = charge on electron

Slope=BCAB=Ek2Ek1V2V1 or slope =ΔEkΔV

But ΔEk=hΔVh=ΔEkΔv
slope = h (Planck's constant)


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