Question

The slope of the graph of the maximum kinetic energy (in joule) of the photoelectrons versus the frequency difference $(v-v_0)$ in a photoelectric experiment is a measure of

• A. h
• B. h/e
• C. e/h
• D. 1/h

Answer 1

The correct option is A

h

Here h = Planck’s constant and e = charge on electron

$Slope=\frac{BC}{AB}=\frac{E_{k_2}-E_{k_1}}{V_2-V_1}orslope=\frac{\Delta E_k}{\Delta V}$

$But\Delta Ek=h\Delta V\Rightarrow h=\frac{\Delta E_k}{\Delta v}$
$\therefore \text{slope = h (Planck's constant)}$