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Equation of a Line Perpendicular to a Given Line

The slope of ...

Question

The slope of the line, $l_{1}$ is $\frac{- 3}{5}$ and $l_{1}$ and $l_{2}$ are parallel. Find the slope of $l_{2}$

A

\frac{- 5}{3}

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B

\frac{- 1}{5}

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C

\frac{- 3}{5}

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D

\frac{3}{5}

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Solution

The correct option is B $\frac{- 3}{5}$
Since the two parallel lines have equal slopes therefore, slope of $l_{1}$ should be equal to slope of $l_{2}$ .
It is given that slope of $l_{1}$ is $- \frac{3}{5}$ ,
Hence, the slope of $l_{2}$ is $- \frac{3}{5}$

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Q. The slope of the line,

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5

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are parallel. Find the slope of

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and the slope of

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L_{1} : \frac{x - 1}{2} = \frac{y - 2}{1} = \frac{z - 3}{1}

L_{2} : \frac{x}{1} = \frac{y}{- 1} = \frac{z - 5}{3}

The equation of the line perpendicular to

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\frac{x}{5} + \frac{y}{b} = 1

passes through the point

M (13, 32)

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