The slope of the normal to the curve x - a -sin- y - a 1-cos- at -2 isA- 0B- 1C- -1 D- 1-2

The correct option is C 1 slope of normal= 1/ ( dy/dx/θ = π/2 )= 1/1= 1 ...

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Equation of Tangent at a Point (x,y) in Terms of f'(x)

The slope of ...

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The slope of the normal to the curve $x = a (θ - s i n θ), y = a (1 - c o s θ) a t θ = \frac{π}{2}$ is

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Similar questions

The slope of the normal to the curve $x = a (θ + s i n θ), y = a c o s θ a t θ = \frac{π}{4}$ is

x = a (θ + s i n θ), y = a (1 - c o s θ)

θ = \frac{π}{2}

x = a (θ + sin θ)

y = a (1 - cos θ)

θ = \frac{π}{2}

x = a (θ - sin θ), y = a (1 - cos θ)

θ = \frac{π}{2}

x = a (θ - sin θ), y = a (1 + cos θ)

θ = - \frac{π}{2}

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