The given equation of curve is,
y=2 x 2 +3sinx
The equation of slope of the tangent to the curve at x=0 is,
( dy dx ) x=0 = ( 4x+3cosx ) x=0 =0+3cos0 =3
The equation of slope of the normal to the curve is,
slope of normal= −1 slope of tangent
For the given curve, equation of slope of the normal is,
slope of normal= −1 3
Thus, the correct option is (D).
The slope of normal to the curve y=2x2+3 sin x at x = 0 is