The slope of the normal to the curve $y = 2 x^{2} + 3 sin x$ at $x = 0$ is.

3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{1}{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

- 3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

- \frac{1}{3}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is B $- \frac{1}{3}$
$y = 2 x^{2} + 3 sin x$
$\frac{d y}{d x} = 4 x + 3 cos x$
Thus slope of tangent at $x = 0$ is $4 (0) + 3 cos 0 = 3$
Hence slope of normal at the same point is $- \frac{1}{m} = - \frac{1}{3}$

Suggest Corrections

Similar questions

The slope of the normal to the curve y = 2x² + 3 sin x at x = 0 is

(A) 3 (B) (C) −3 (D)

The slope of normal to the curve $y = 2 x^{2} + 3 s i n x$ at x = 0 is

Chose the correct answer.

The slope of the normal to the curve $y = 2 x^{2} + 3$ sinx at x=0 is

(a) 3 (b) $\frac{1}{3}$ (c)-3 (d)- $\frac{1}{3}$

x^{2 / 3} + y^{2 / 3} = 2

Join BYJU'S Learning Program