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Arrhenius Equation

The slope of ...

Question

The slope of the straight line obtained by plotting $l o g_{10}$ k against $1 / T$ represents :

- E_{a}

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- 2.303 E_{a} / R

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- E_{a} / 2.303 R

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- E_{a} / R

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Solution

The correct option is C $- E_{a} / 2.303 R$
The Arrhenius equation is:

$l o g_{10} k = l o g_{10} A - \frac{E_{a}}{2.303 R T}$

The y-intercept is $l o g_{10} A$ .

The slope is $\frac{- E_{a}}{2.303 R}$ .

Hence, option $C$ is correct.

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