You visited us 4 times! Enjoying our articles? Unlock Full Access!

Arrhenius Equation

The slope of ...

Question

The slope of the straight line obtained by plotting $l o g_{10}$ k against $1 / T$ represents :

- E_{a}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

- 2.303 E_{a} / R

No worries! We‘ve got your back. Try BYJU‘S free classes today!

- E_{a} / 2.303 R

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

- E_{a} / R

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $- E_{a} / 2.303 R$
The Arrhenius equation is:

$l o g_{10} k = l o g_{10} A - \frac{E_{a}}{2.303 R T}$

The y-intercept is $l o g_{10} A$ .

The slope is $\frac{- E_{a}}{2.303 R}$ .

Hence, option $C$ is correct.

Suggest Corrections

Similar questions

k

1 / T

k = A . e^{- E_{a} / (R T)}

k

log k = c o n s t a n t - \frac{E_{a}}{2.303 R} \times \frac{1}{T}

E_{a}

log k

\frac{1}{T}

- 6670 k

R = 8.314 J K^{- 1} {m o l}^{- 1})

k = A e^{- E_{a} / R T}

log k

1 / T

k = A e^{- E a / R T}

E_{a}

k = A e^{- E_{a} / R T}

E_{a}

Join BYJU'S Learning Program