Question

The slope of the straight line whose inclination is ${60}^{\circ }$ is

• A. $0$
• B. $\frac{1}{\sqrt{3}}$
• C. $-\sqrt{3}$
• D. $\sqrt{3}$

Answer 1

The correct option is D $\sqrt{3}$

Solution:

Slope of a straight line $m=\tan \theta$

or, $m=\tan {60}^{\circ }$

or, $m=\sqrt{3}$

Therefore, $D$ is the correct answer.