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Question

The slope of the tangent to the curve x=3t2+1,y=t31 at x=1 is

A
12
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B
0
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C
2
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D
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Solution

The correct option is A 0
Given, x=3t2+1,y=t31
Slope of the tangent to the given curve is dydx=dydt×dtdx
=3t2×16t
=t2
Since the slope has to be calculated at x=1, i.e. at 3t2+1=1, we get t=0
Thus, the required slope is 0.

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