The slope of the tangent to the curve y=sinx where it crosses the x−axis is
Consider the given equation of the curve.
y=sinx ……(1)
On differentiating equation (1) with respect to x, we get
dydx=cosx
When given curve crosses the x-axis then.
y=0
sinx=0
x=0
Therefore,
(dydx)y=0=cos0
(dydx)y=0=1
Hence, this is the answer.