The slope of the tangent to the curve y=√4−x2 at the point where the ordinate and the abscissa are equal is
A
-1
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B
1
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C
0
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D
none of these
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Solution
The correct option is A -1 Given equation of curve is y=√4−x2 y2=4−x2 ⇒dydx=−xy Let P(x1,y1) be the point on the curve such that x1=y1 So, slope of tangent to curve at P is −1.