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Question

The slope of the tangent to the curve y=x2−x at the point where the line y=2 cuts the curve in the first quadrant is

A
2
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B
3
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C
3
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D
none of these
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Solution

The correct option is B 3
For y=2,x2x2=0 gives x=1 and x=2 as point is in first quadrant.
Therefore point is (2,2)
Now dydx=2x1=41=3

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