wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The slopes of the normals to the parabola y2=4ax intersecting at a point on the axis of the parabola at a distance 4a, from its vertex are in

A
A.P.
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
G.P.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
H.P.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
None of these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A A.P.
Equation for normal to the parabola y2=4ax is
y=mx2amam3......(1)
Normal intersecting at a point on the axis of the parabola at a distance 4a from its vertex i.e at (4a,0)
Substitute the point in equation.... (1)
0=4am2amam3am(m22)=0
m=0, ±2
Therefore roots can be written as 2, 0, 2 which is in A.P.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Extrema
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon