The small bob A of a simple pendulum released from certain height to the vertical, hits another bob of the same mass and size lying at rest on the table vertically below the point of suspension. After elastic collision, the angular amplitude of the bob A will be :

30

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60

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15

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z e r o

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Solution

The correct option is D $z e r o$
Let $v$ be the velocity of A at time of collision, and final velocity of both of them be $v_{1} a n d v_{2}$ since it is elastic collision, coeff. of restitution is 1.
$v = v_{2} - v_{1}$
Conservation of momentum:
$m v = m v_{1} + {m v}_{2}$
Solving these two equations we get, $v_{2} = v$ and $v_{1} = 0$
So, the pendulum A will come to rest and have angular amplitude to be zero.

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Q. The bob

A

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30^{o}

to the vertical hits another bob

B

of the same mass at rest on a table as shown in fig. How high does the bob

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rise after the collision ? Neglect the size of the bobs and assume the collision to be elastic.

The bob A of a pendulum released from 30° to the vertical hits another bob B of the same mass at rest on a table as shown in Fig. 6.15. How high does the bob A rise after the collision? Neglect the size of the bobs and assume the collision to be elastic.