The smallest $3$ -digit number $=$ the greatest _______ digit number $+ 1$

Open in App

Solution

The smallest $3$ -digit number $=$ the greatest $2$ -digit number $+ 1$ .
smallest $3$ -digit number $= 100$
greatest $2$ -digit number $= 99$
Therefore, $100 = 99 + 1$

Suggest Corrections

Similar questions

Write the greatest and smallest $5$ -digit numbers with the digits:

$1, 0, 3$

3

2

Find the products between

The smallest $3$ -digit number and the greatest $2$ -digit number.

Find the products between

The greatest $5$ -digit number and the smallest $3$ -digit number.

Join BYJU'S Learning Program