The smallest 5 digit number exactly divisible by $41$ is:

1004

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10004

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10045

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10025

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None of these

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Solution

The correct option is B $10004$
The smallest 5-digit number $= 10000$
$10000 \div 41$ (Quotient $= 243$ ; Remainder $= 37$ )
Required number $= 10000 + (41 - 37)$
$= 10004$ .

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