Question

The smallest 5 digit number exactly divisible by $41$ is:

• A. $1004$
• B. $10004$
• C. $10045$
• D. $10025$
• E. None of these

Answer 1

The correct option is B $10004$

The smallest 5-digit number $=10000$
$10000÷41$ (Quotient$=243$; Remainder$=37$)
Required number $=10000+(41-37)$
$=10004$.