The smallest division on the main scale of a Vernier callipers is $1 mm$ and 10 vernier divisions coincide with 9 main scale divisions. While measuring the diameter of a ring, the zero mark of the vernier scale lies between $5.0 cm$ and $5.1 cm$ and the eighth division of the vernier scale coincides with a main scale division. The diameter of the ring is :

5.06 cm

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5.08 cm

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5.04 cm

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5.02 cm

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Solution

The correct option is B $5.08 cm$
$10 V S D = 9 M S D$
$1 V S D = 0.9 M S D$
$1 V S D = 0.9 \times 1 mm = 0.9 mm$
Least count = $1 M S D - 1 V S D = 0.1 mm$

Reading = main scale reading + vernier scale reading $= 5.0 + 8 \times 0.01 = 5.08 cm$ .

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The correct option is B 5.08 cm10 VSD=9 MSD 1 VSD=0.9 MSD 1 VSD=0.9×1 mm=0.9 mm Least count = 1 MSD−1 VSD=0.1 mm Reading = main scale reading + vernier scale reading =5.0+8×0.01=5.08 cm.

The correct option is B $5.08 cm$
$10 V S D = 9 M S D$
$1 V S D = 0.9 M S D$
$1 V S D = 0.9 \times 1 mm = 0.9 mm$
Least count = $1 M S D - 1 V S D = 0.1 mm$

Reading = main scale reading + vernier scale reading $= 5.0 + 8 \times 0.01 = 5.08 cm$ .