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Question

The smallest integral value of p for which the inequality (p3)x22px+3(p2)>0 is satisfied for all real values of x is

A
8
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B
7
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C
6
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D
5
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Solution

The correct option is D 7
f(x)>0 when D<0 and p>3
4p212(p3)(p2)<0
2p215p+18>0
(p6)(2p3)>0
p<32 or p>6
Hence, smallest integral value of p is 7.

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