The smallest ketone and its next homologue are reacted with $N H_{2} O H$ to form:

two different oxime

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four different oxime

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three different oxime

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optically active oxime

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Solution

The correct option is C three different oxime

The lowest molecular weight ketone is $M e - C O - M e$ and its nest homologue is $M e C H_{2} - C O - M e$

Therefore, correct option is $C$ .

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