Question

The smallest natural number by which $2401$ must be divided to get a perfect cube is?

• A. $7$
• B. $1$
• C. $2$
• D. $5$

Answer 1

The correct option is A $7$

Prime factorising $2401$, we get,

$2401=7^4$.

Number of $7$'s here is $4$.

So we need to divide the factorization by $7$ to make $2401$ a perfect cube.

Hence, the smallest number by which $2401$ must be divided to obtain a perfect cube is $7$.

Therefore, option $A$ is correct.