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Question

The smallest natural number of the form 123X43Y, which is exactly divisible by 6 is______

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Solution

Factor of 6=2,3

If 123X43Y is divisible by 2 then its unit digit should be 0,2,4,6,8 and the number for being divisible of 3, the sum of its digits (13+X+Y) should be divisible by 3


Hence,

X+Y=2


So,

When X=0,Y=2

Therefore the number is 1230432.


Or

When X=2,Y=0

Therefore the number is 1232430.

As per the given condition of the smallest number, the correct answer is 1230432.


Hence, this is the answer.


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