The smallest number by which 2560 must be multiplied so that the product is a perfect cube is?
Prime factorising 2560, we get,
2560=29×5.
We know, a perfect cube has multiples of 3 as powers of prime factors.
Here, number of 2's is 9 and number of 5's is 1.
So we need to multiply another 52 in the factorization to make 2560 a perfect cube.
Hence, the smallest number by which 2560 must be multiplied to obtain a perfect cube is 52=25.