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Question

The smallest number by which 2560 must be multiplied so that the product is a perfect cube is?

A
5
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B
25
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C
10
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D
15
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Solution

The correct option is B 25

Prime factorising 2560, we get,

2560=29×5.

We know, a perfect cube has multiples of 3 as powers of prime factors.

Here, number of 2's is 9 and number of 5's is 1.

So we need to multiply another 52 in the factorization to make 2560 a perfect cube.

Hence, the smallest number by which 2560 must be multiplied to obtain a perfect cube is 52=25.

Therefore, option B is correct.

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